Junior Puzzle #6 - One Possible Solution Approach…
	NB:  There is only one final solution to this Sudoku puzzle…
	A	B	C	D	E	F	G	H	I
1
2	AA			BB			CC				Reference to 3x3 Blocks AA, BB & CC
3
4
5	DD			EE			FF				Reference to 3x3 Blocks DD, EE & FF
6
7
8	GG			HH			II				Reference to 3x3 Blocks GG, HH & II
9
	A	B	C	D	E	F	G	H	I
1				2	9	4	8	3	5		Junior Puzzle #6 - November 12, 2005
2	5	4	9				1	2	7		Original puzzle as published © joe-ks.com
3	2	8	3	5	7	1
4	1			3	2	5	7	9	8
5	7	5	2	1			3	6	4
6	9	3	8	6	4	7	2
7	4	7		9	3	2	5	8	6
8	3	9	6	7	5		4	1	2
9	8	2	5	4	1	6	9	7
	A	B	C	D	E	F	G	H	I
1	6			2	9	4	8	3	5		Step 1: Column A needs one more #: #6 Must go in Cell A1...
2	5	4	9	8			1	2	7
3	2	8	3	5	7	1	6				Step 2: Column D needs one more #: #8 Must go in Cell D2...
4	1			3	2	5	7	9	8
5	7	5	2	1			3	6	4		Step 3: Column G needs one more #: #6 Must go in Cell G3...
6	9	3	8	6	4	7	2
7	4	7		9	3	2	5	8	6
8	3	9	6	7	5		4	1	2
9	8	2	5	4	1	6	9	7
	A	B	C	D	E	F	G	H	I
1	6			2	9	4	8	3	5		Step 4: Row 7 needs one more #: #1 MUST go in Cell C7…
2	5	4	9	8			1	2	7
3	2	8	3	5	7	1	6				Step 5: Row 8 needs one more #: #8 MUST go in Cell F8…
4	1			3	2	5	7	9	8
5	7	5	2	1			3	6	4		Step 6: Row 9 needs one more #: #3 MUST go in Cell I9…
6	9	3	8	6	4	7	2
7	4	7	1	9	3	2	5	8	6
8	3	9	6	7	5	8	4	1	2
9	8	2	5	4	1	6	9	7	3
	A	B	C	D	E	F	G	H	I
1	6			2	9	4	8	3	5		Step 7: Complete Row 6: need 2 more numbers: #1 & #5…
2	5	4	9	8			1	2	7		#1 can't go in Cell H6 (because #1 is already in Column H
3	2	8	3	5	7	1	6				@ H8 - and #1 can only go once in Column H), so
4	1			3	2	5	7	9	8		#1 MUST go in Cell I6, & therefore the other # (#5) MUST
5	7	5	2	1			3	6	4		go in the only remaining Cell - at Cell H6
6	9	3	8	6	4	7	2	5	1
7	4	7	1	9	3	2	5	8	6
8	3	9	6	7	5	8	4	1	2
9	8	2	5	4	1	6	9	7	3
	A	B	C	D	E	F	G	H	I
1	6			2	9	4	8	3	5		Now we only need one number for Columns H & I…
2	5	4	9	8			1	2	7		Step 8: Completet Column H: #4 MUST go in Cell H3…
3	2	8	3	5	7	1	6	4	9
4	1			3	2	5	7	9	8		Step 9: Complete Column I: #9 MUST go in Cell I3…
5	7	5	2	1			3	6	4
6	9	3	8	6	4	7	2	5	1
7	4	7	1	9	3	2	5	8	6
8	3	9	6	7	5	8	4	1	2
9	8	2	5	4	1	6	9	7	3
	A	B	C	D	E	F	G	H	I
1	6			2	9	4	8	3	5		Step 10: Complete Block EE: need #s 8 & 9…
2	5	4	9	8			1	2	7		#9 can't go in Cell E5 (cf #9 in Column E @ E1), so
3	2	8	3	5	7	1	6	4	9		#9 MUST go in Cell F5, & therefore #8 MUST go in Cell E5
4	1			3	2	5	7	9	8
5	7	5	2	1	8	9	3	6	4
6	9	3	8	6	4	7	2	5	1
7	4	7	1	9	3	2	5	8	6
8	3	9	6	7	5	8	4	1	2
9	8	2	5	4	1	6	9	7	3
	A	B	C	D	E	F	G	H	I
1	6			2	9	4	8	3	5		Step 11: Complete Column E: #6 MUST go in Cell E2...
2	5	4	9	8	6	3	1	2	7
3	2	8	3	5	7	1	6	4	9		Step 12: Complete Column F: #3 MUST go in Cell F2...
4	1			3	2	5	7	9	8
5	7	5	2	1	8	9	3	6	4
6	9	3	8	6	4	7	2	5	1
7	4	7	1	9	3	2	5	8	6
8	3	9	6	7	5	8	4	1	2
9	8	2	5	4	1	6	9	7	3
	A	B	C	D	E	F	G	H	I
1	6	1	7	2	9	4	8	3	5		Step 13: Complete Block AA: need #s 1 & 7…
2	5	4	9	8	6	3	1	2	7		#1 can't go in Cell C1 (see #1 in Column C @ C7), so
3	2	8	3	5	7	1	6	4	9		#1 MUST go in Cell B1, & therefore #7 MUST go in Cell C1
4	1			3	2	5	7	9	8
5	7	5	2	1	8	9	3	6	4
6	9	3	8	6	4	7	2	5	1
7	4	7	1	9	3	2	5	8	6
8	3	9	6	7	5	8	4	1	2
9	8	2	5	4	1	6	9	7	3
	A	B	C	D	E	F	G	H	I
1	6	1	7	2	9	4	8	3	5		Step 14: Complete Block DD (& complete the Puzzle):
2	5	4	9	8	6	3	1	2	7		need #s 4 & 6…
3	2	8	3	5	7	1	6	4	9		#4 can't go in Cell B4 (see #4 in Column B @ B2), so
4	1	6	4	3	2	5	7	9	8		#4 MUST go in Cell C4, & thererfore #6 MUST go in Cell B4.
5	7	5	2	1	8	9	3	6	4
6	9	3	8	6	4	7	2	5	1
7	4	7	1	9	3	2	5	8	6
8	3	9	6	7	5	8	4	1	2
9	8	2	5	4	1	6	9	7	3
	A	B	C	D	E	F	G	H	I
1	6	1	7	2	9	4	8	3	5	45	Final Proof:
2	5	4	9	8	6	3	1	2	7	45	- All Rows add up to 45;
3	2	8	3	5	7	1	6	4	9	45
4	1	6	4	3	2	5	7	9	8	45
5	7	5	2	1	8	9	3	6	4	45
6	9	3	8	6	4	7	2	5	1	45
7	4	7	1	9	3	2	5	8	6	45
8	3	9	6	7	5	8	4	1	2	45
9	8	2	5	4	1	6	9	7	3	45
	45	45	45	45	45	45	45	45	45		- All Columns add up to 45;
	45			45			45				- All 3x3 Blocks add up to 45…
	45			45			45
	45			45			45